A discontinuity with a concave surface will cause the reflected beam to focus at a point.

A discontinuity with a concave surface will cause the reflected beam to focus at a point.

• A. True
• B. False
• C. It will diffuse the energy
• D. It will not reflect

Answer: (A)

A concave surface acts like a lens for the ultrasonic beam, causing the reflected rays to converge toward a common point along the beam axis. Because reflection follows the angle of incidence equals angle of reflection at every point on the curved surface, the waves from different parts of the surface are redirected so they meet at a focal point. This concentrates energy and produces a strong, localized echo from the discontinuity when the focal point aligns with it. So the statement is true: the concave surface will focus the reflected beam at a point. The idea of energy being diffused doesn’t apply to a smooth concave reflector, and it certainly doesn’t imply no reflection.

A concave surface acts like a lens for the ultrasonic beam, causing the reflected rays to converge toward a common point along the beam axis. Because reflection follows the angle of incidence equals angle of reflection at every point on the curved surface, the waves from different parts of the surface are redirected so they meet at a focal point. This concentrates energy and produces a strong, localized echo from the discontinuity when the focal point aligns with it. So the statement is true: the concave surface will focus the reflected beam at a point. The idea of energy being diffused doesn’t apply to a smooth concave reflector, and it certainly doesn’t imply no reflection.